c^2-0.5c=0.125

Solution for c^2-0.5c=0.125 equation:

c^2-0.5c=0.125

We move all terms to the left:

c^2-0.5c-(0.125)=0

We add all the numbers together, and all the variables

c^2-0.5c-0.125=0

a = 1; b = -0.5; c = -0.125;
Δ = b2-4ac
Δ = -0.52-4·1·(-0.125)
Δ = 0.75
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{0.75}}{2*1}=\frac{0.5-\sqrt{0.75}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{0.75}}{2*1}=\frac{0.5+\sqrt{0.75}}{2}
$